0=x^2+19x+70

Solution for 0=x^2+19x+70 equation:

0=x^2+19x+70

We move all terms to the left:

0-(x^2+19x+70)=0

We add all the numbers together, and all the variables

-(x^2+19x+70)=0

We get rid of parentheses

-x^2-19x-70=0

We add all the numbers together, and all the variables

-1x^2-19x-70=0

a = -1; b = -19; c = -70;
Δ = b2-4ac
Δ = -192-4·(-1)·(-70)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-9}{2*-1}=\frac{10}{-2}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+9}{2*-1}=\frac{28}{-2}
=-14
$